Giúp mình hai bài này với

Bài 2:

$a,PTHH:2C_4H_{10}+13O_2\xrightarrow{t^o}8CO_2+10H_2O$

$b,n_{CO_2}=\dfrac{35,2}{44}=0,8(mol)$

Theo PT: $n_{C_4H_{10}}=\dfrac{1}{4}n_{CO_2}=0,2(mol);n_{O_2}=\dfrac{13}{8}n_{CO_2}=1,3(mol)$

$\Rightarrow m_{C_4H_{10}}=0,2.58=11,6(g);m_{O_2}=1,3.32=41,6(g)$

Bài 3:

$a,PTHH:C+O_2\xrightarrow{t^o}CO_2$

$S+O_2\xrightarrow{t^o}SO_2$

$b,n_C=n_{hh}-n_S=0,7(mol)$

$\Rightarrow \Sigma n_{O_2}=n_C+n_S=0,3+0,7=1(mol)$

$\Rightarrow V_{O_2}=1.22,4=22,4(l)$