Giải phương trình 3x(x-2)=2x-4

$3x(x-2)=2x-4$

$⇔3x(x-2)=2(x-2)$

$⇔3x(x-2)-2(x-2)=0$

$⇔(x-2)(3x-2)=0$

⇔\(\left[ \begin{array}{l}x-2=0\\3x-2=0\end{array} \right.\)

⇔\(\left[ \begin{array}{l}x=2\\x=2/3\end{array} \right.\) 

 $Vậy$ $x=2$ $hoặc$ $x=2/3.$