Bài `2` `a,` `132 -2(x-4) = 46 ` ` 2(x-4) = 132 - 46 ` ` 2(x-4) = 86 ` ` x-4 = 86 : 2 ` ` x-4 = 43 ` `x = 43-4 ` ` x = 39 ` `b,` `9x -4x = 6^17 : 6^15 + 48 : 12 ` `5x = 6^ 2 + 4 ` `5x = 32 ` `x = 32 : 5` `x = 6,4 ` `c. ` `2^x+3 * 4^2 = 64 ` ` 2^x+3 = 64 : 4^2 ` ` 2^x+3 = 64 : 16 ` `2^x+3 = 4 ` `x+3 = 4:2` `x+3 = 2` `x= -1` `d,` ` 6` chia hết `(x+2)` .Mà `x` ∈ `Z` Vậy `(x+2)` ∈ Ước `(6)` `=>` `x` = `[ -1,-3,0,-4,1,-5,4,-8]`

`2)` `a)132-2(x-4)=46` `2(x-4)=132-46` `2(x-4)=86` `x-4=86:2` `x-4=43` `x=43+4` `x=47` `b)9x-4x=6^17:6^15+48:12` `x(9-4)=36+4` `x5=40` `x=40:5` `x=8` `c)2^(x+3).4^2=64` `2^(x+3)=64:16` `2^(x+3)=4` `2^(x+3)=2^2` `=>x+3=2` `=>x=2-3` `=>x=-1` `d)6vdots(x+2)` `=>x+2in Ư(6)` `=>x+2={+-1;+-2;+-3;+-6}` `=>x={-1;-3;0;-4;1;-5;4;-8}`