9x(x-2014)-x+2014=0

Đáp án:

 $9x.(x-2014)-x+2014=0$

$⇔ 9x.(x-2014)-(x-2014)=0$

$⇔ (9x-1).(x-2014)=0$

$⇔$ \(\left[ \begin{array}{l}9x-1=0\\x-2014=0\end{array} \right.\) $⇔$  \(\left[ \begin{array}{l}9x=1\\x=2014\end{array} \right.\)$⇔$  \(\left[ \begin{array}{l}x=\dfrac{1}{9}\\x=2014\end{array} \right.\) 

$vậy$ $x=\dfrac{1}{9}$ $hoặc$ $x=2014$