Hộ mình bài này vớiiiii ạ

`d)`

`(-1/2)^(3).2 1/3.(-2)^(3)-1/3`

`=(-1/2)^(3).(-2)^(3).2 1/3-1/3`

`=(-1/(2).(-2))^(3).(7)/3-1/3`

`=1^(3).(7)/3-1/3`

`=7/3-1/3`

`=6/3=2`

`e)`

`(2^(7).9^2)/(3^(2).2^5)`

`=(2^(5).2^(2).9^2)/(9.2^5)`

`=2^(2).9`

`=4.9`

`=36`

Bài `2` :

`a)`

`3 3/4-(x+1/2)=4/5`

`⇒15/4-(x+1/2)=4/5`

`⇒x+1/2=15/4-4/5`

`⇒x+1/2=59/20`

`⇒x=59/20-1/2`

`⇒x=49/20`

Vậy `x=49/20`

`b)`

`(1/3x):(2)/3=4 3/8`

`⇒(1/3x):(2)/3=35/8`

`⇒1/3x=35/8.(2)/3`

`⇒1/3x=35/12`

`⇒x=35/4`

Vậy `x=35/4`

`c)`

`1 2/3x-1/4=5/6`

`⇒5/3x-1/4=5/6`

`⇒5/3x=5/6+1/4`

`⇒5/3x=13/12`

`⇒x=13/20`

`d)`

`|2x-1|-1/2=1/3`

`⇒|2x-1|=1/3+1/2`

`⇒|2x-1|=5/6`

$⇒\left[\begin{matrix}2x-1=\dfrac{5}{6}\\ 2x-1=\dfrac{-5}{6}\end{matrix}\right.$

$⇒\left[\begin{matrix}2x=\dfrac{5}{6}+1\\ 2x=\dfrac{-5}{6}+1\end{matrix}\right.$

$⇒\left[\begin{matrix}2x=\dfrac{11}{6}\\ 2x=\dfrac{1}{6}\end{matrix}\right.$

$⇒\left[\begin{matrix}x=\dfrac{11}{12}\\ x=\dfrac{1}{12}\end{matrix}\right.$

Vậy `x∈{11/12;1/12}`