giúp mình hạn trước 9h trưa nay hứa vote đầy đủ

Đáp án:

$\begin{array}{l}
1)a){\left( {\dfrac{3}{2}} \right)^2} - \left[ {\dfrac{1}{2}:2 - \sqrt {{{\left( { - 9} \right)}^2}} .\dfrac{1}{3}} \right]\\
 = \dfrac{9}{4} - \left( {\dfrac{1}{4} - 9.\dfrac{1}{3}} \right)\\
 = \dfrac{9}{4} - \dfrac{1}{4} + 3\\
 = 2 + 3\\
 = 5\\
b)\left| { - \dfrac{{100}}{{123}}} \right|:\left( {\dfrac{3}{4} + \dfrac{7}{{12}}} \right) + \dfrac{{23}}{{123}}:\left( {\dfrac{9}{5} - \dfrac{7}{{15}}} \right)\\
 = \dfrac{{100}}{{123}}:\dfrac{{16}}{{12}} + \dfrac{{23}}{{123}}:\dfrac{{20}}{{15}}\\
 = \dfrac{{100}}{{123}}.\dfrac{3}{4} + \dfrac{{23}}{{123}}.\dfrac{3}{4}\\
 = \dfrac{3}{4}.\left( {\dfrac{{100}}{{123}} + \dfrac{{23}}{{123}}} \right)\\
 = \dfrac{3}{4}.\dfrac{{123}}{{123}}\\
 = \dfrac{3}{4}\\
c)\dfrac{{{{\left( { - 5} \right)}^{32}}{{.20}^{43}}}}{{{{\left( { - 8} \right)}^{29}}{{.125}^{25}}}}\\
 = \dfrac{{{5^{32}}{{.2}^{86}}{{.5}^{43}}}}{{ - {2^{3.29}}{{.5}^{3.25}}}}\\
 =  - \dfrac{{{5^{75}}{{.2}^{86}}}}{{{2^{87}}{{.5}^{75}}}}\\
 =  - \dfrac{1}{2}\\
B2)\\
a)\dfrac{2}{3} - \left( {\dfrac{3}{4} - x} \right) = 1\\
 \Leftrightarrow \dfrac{2}{3} - \dfrac{3}{4} + x = 1\\
 \Leftrightarrow x = 1 + \dfrac{3}{4} - \dfrac{2}{3}\\
 \Leftrightarrow x = \dfrac{{13}}{{12}}\\
Vậy\,x = \dfrac{{13}}{{12}}\\
b){\left( {\dfrac{1}{2} - x} \right)^2} = {\left( { - 2} \right)^2}\\
 \Leftrightarrow \left[ \begin{array}{l}
\dfrac{1}{2} - x = 2\\
\dfrac{1}{2} - x =  - 2
\end{array} \right.\\
 \Leftrightarrow \left[ \begin{array}{l}
x = \dfrac{1}{2} - 2 =  - \dfrac{3}{2}\\
x = \dfrac{1}{2} + 2 = \dfrac{5}{2}
\end{array} \right.\\
Vậy\,x =  - \dfrac{3}{2};x = \dfrac{5}{2}
\end{array}$