Làm giúp em với ạ.pls:<

Em tham khảo nha :

\(\begin{array}{l}
a)\\
Zn + {H_2}S{O_4} \to ZnS{O_4} + {H_2}\\
{n_{{H_2}}} = \dfrac{{2,479}}{{24,79}} = 0,1mol\\
{n_{Zn}} = {n_{{H_2}}} = 0,1mol\\
{m_{Zn}} = 0,1 \times 65 = 6,5g\\
b)\\
\% Zn = \dfrac{{6,5}}{{6,5 + 3,2}} \times 100\%  = 67,01\% \\
\% Cu = 100 - 67,01 = 32,99\% \\
c)\\
{n_{Cu}} = \dfrac{{3,2}}{{64}} = 0,05mol\\
Zn + 2AgN{O_3} \to Zn{(N{O_3})_2} + 2Ag\\
Cu + 2AgN{O_3} \to Cu{(N{O_3})_2} + 2Ag\\
{n_{AgN{O_3}}} = 2{n_{Zn}} + 2{n_{Cu}} = 0,3mol\\
{C_{{M_{AgN{O_3}}}}} = \frac{{0,3}}{{0,2}} = 1,5M
\end{array}\)