giúp :33

Đáp án:

$a, (x^2 - 2)(x - 2)$

$b, (x-2y)(x+2y+3)$

$c, (2x+1-y)(2x+1+y)$

$d (x-y)(x^2+xy+y^2-x-y)$

Giải thích các bước giải:

$a, x^3 - 2x^2 - 2x + 4$

$= (x^3 - 2x^2) + (-2x + 4)$

$= x^2(x - 2) - 2(x - 2)$

$= (x^2 - 2)(x - 2)$

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$b, x^2 - 4y^2 + 3x - 6y$

$= [x^2 - (2y)^2] + (3x - 6y)$

$= (x-2y)(x+2y)+ 3(x-2y) $

$= (x-2y)(x+2y+3)$

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$c, 4x^2+4x+1-y^2$

$= (4x^2+4x+1)-y^2$

$= (2x+1)^2-y^2$

$= (2x+1-y)(2x+1+y)$

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$d, x^3-y^3-x^2+y^2$

$= (x^3-y^3)-(x^2-y^2)$

$= (x-y)(x^2+xy+y^2)-(x-y)(x+y)$

$= (x-y)(x^2+xy+y^2-x-y)$

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