bài nào cx dc trừ bài 1

Đáp án:

$\begin{array}{l}
B1)\\
y = \dfrac{2}{3}x + 5\\
 + f\left( { - 5} \right) = \dfrac{2}{3}.\left( { - 5} \right) + 5 = \dfrac{5}{3}\\
 + f\left( { - 4} \right) = \dfrac{2}{3}.\left( { - 4} \right) + 5 = \dfrac{7}{3}\\
 + f\left( { - 1} \right) = \dfrac{2}{3}.\left( { - 1} \right) + 5 = \dfrac{{13}}{3}\\
 + f\left( 0 \right) = \dfrac{2}{3}.0 + 5 = 5\\
 + f\left( {\dfrac{1}{2}} \right) = \dfrac{2}{3}.\dfrac{1}{2} + 5 = \dfrac{{16}}{3}\\
 + f\left( 1 \right) = \dfrac{2}{3}.1 + 5 = \dfrac{{17}}{3}\\
 + f\left( 2 \right) = \dfrac{2}{3}.2 + 5 = \dfrac{{19}}{3}\\
 + f\left( 4 \right) = \dfrac{2}{3}.4 + 5 = \dfrac{{23}}{3}
\end{array}$