(2x-1)mũ 4=(2x-1) mũ 6

`(2x-1)^4=(2x-1)^6`

`⇒(2x-1)^6-(2x-1)^4=0`

`(2x-1)^4.[(2x-1)^2-1)=0`

`⇒`\(\left[ \begin{array}{l}(2x-1)^{4}=0\\(2x-1)^{2}-1=0\end{array} \right.\) 

`⇒`\(\left[ \begin{array}{l}2x-1=0\\(2x-1)^{2}=1\end{array} \right.\) 

`⇒`\(\left[ \begin{array}{l}2x=1\\2x-1=±1\end{array} \right.\) 

`⇒`\(\left[ \begin{array}{l}x=\dfrac{1}{2}\\2x∈{0;2}\end{array} \right.\) 

`⇒`\(\left[ \begin{array}{l}x=\dfrac{1}{2}\\x∈{0;1}\end{array} \right.\) 

Vậy `x ∈ {1/2;0;1}`