Tìm tập nghiệm của phương trình cos x.sin (2x- $\frac{\pi}{3}$)=0 Ai giúp mình với ạ, hứa vote 5 sao ạ

`~rai~`

\(\cos x.\sin\left(2x-\dfrac{\pi}{3}\right)=0\\\Leftrightarrow \left[\begin{array}{I}\cos x=0\\\sin\left(2x-\dfrac{\pi}{3}\right)=0\end{array}\right.\\\Leftrightarrow \left[\begin{array}{I}x=\dfrac{\pi}{2}+k\pi\\2x-\dfrac{\pi}{3}=k\pi\end{array}\right.\\\Leftrightarrow \left[\begin{array}{I}x=\dfrac{\pi}{2}+k\pi\\2x=\dfrac{\pi}{3}+k\pi\end{array}\right.\\\Leftrightarrow \left[\begin{array}{I}x=\dfrac{\pi}{2}+k\pi\\x=\dfrac{\pi}{6}+k\dfrac{\pi}{2}.\end{array}\right.\quad(k\in\mathbb{Z})\\\text{Vậy S=}\left\{\dfrac{\pi}{2}+k\pi;\dfrac{\pi}{6}+k\dfrac{\pi}{2}\Big|k\in\mathbb{Z}\right\}.\)