(3-1/2x)(|x+3/4|-5/6)=0

` (3 - 1/2x )(|x+3/4| - 5/6) = 0`

`=>` \(\left[ \begin{array}{l}3- 1/2 x =0 \\|x + 3/4| - 5/6 = 0\end{array} \right.\) 

`TH1 : 3 - 1/2x = 0`

`=> 1/2x = 3`

`=> x = 6`

`TH2 : |x+3/4| - 5/6 = 0`

`=> |x+3/4| = 5/6`

`TH* : x + 3/4 = 5/6`

`=> x = 1/12`

`TH** : x + 3/4 = -5/6`

`=> x = -19/12`

Vậy `x = \{ 6 ; 1/12 ; -19/12 \}`