mọi người làm ơn giúp mik ạ hứa vote 5* Tối là mik nộp r ạ Cảm Ơn

Đáp án:

\(\begin{array}{l}
1,\,\,2\sqrt 2 \\
2,\,\,\,4\sqrt 3 \\
3,\,\,\,5\sqrt 3 \\
4,\,\,\,\,5\sqrt 2 \\
5,\,\,\,7\sqrt 2 \\
6,\,\,\,2\sqrt 7 \\
7,\,\,\,5\sqrt 6 \\
8,\,\,\,2\sqrt 6 \\
9,\,\,\,2\sqrt {x + 2} \\
10,\,\,\,4\sqrt {2{x^2} + 1} \\
11,\,\,\,5\sqrt {1 - 2x} \\
12,\,\,\,3\sqrt {x + 1} \\
13,\,\,\,6\sqrt {x - 2} 
\end{array}\)

Giải thích các bước giải:

 Ta có:

\(\begin{array}{l}
1,\,\,\sqrt 8  = \sqrt {4.2}  = \sqrt {{2^2}.2}  = 2\sqrt 2 \\
2,\,\,\,\sqrt {48}  = \sqrt {16.3}  = \sqrt {{4^2}.3}  = 4\sqrt 3 \\
3,\,\,\,\sqrt {75}  = \sqrt {25.3}  = \sqrt {{5^2}.3}  = 5\sqrt 3 \\
4,\,\,\,\,\sqrt {50}  = \sqrt {25.2}  = \sqrt {{5^2}.2}  = 5\sqrt 2 \\
5,\,\,\,\sqrt {98}  = \sqrt {49.2}  = \sqrt {{7^2}.2}  = 7\sqrt 2 \\
6,\,\,\,\sqrt {28}  = \sqrt {4.7}  = \sqrt {{2^2}.7}  = 2\sqrt 7 \\
7,\,\,\,\sqrt {150}  = \sqrt {25.6}  = \sqrt {{5^2}.6}  = 5\sqrt 6 \\
8,\,\,\,\sqrt {24}  = \sqrt {4.6}  = \sqrt {{2^2}.6}  = 2\sqrt 6 \\
9,\,\,\,\sqrt {4x + 8}  = \sqrt {4.\left( {x + 2} \right)}  = \sqrt {{2^2}.\left( {x + 2} \right)}  = 2\sqrt {x + 2} \\
10,\,\,\,\sqrt {32{x^2} + 16}  = \sqrt {16.\left( {2{x^2} + 1} \right)}  = \sqrt {{4^2}.\left( {2{x^2} + 1} \right)}  = 4\sqrt {2{x^2} + 1} \\
11,\,\,\,\sqrt {25 - 50x}  = \sqrt {25.\left( {1 - 2x} \right)}  = \sqrt {{5^2}.\left( {1 - 2x} \right)}  = 5\sqrt {1 - 2x} \\
12,\,\,\,\sqrt {9x + 9}  = \sqrt {9\left( {x + 1} \right)}  = \sqrt {{3^2}.\left( {x + 1} \right)}  = 3\sqrt {x + 1} \\
13,\,\,\,\sqrt {36x - 72}  = \sqrt {36\left( {x - 2} \right)}  = \sqrt {{6^2}.\left( {x - 2} \right)}  = 6\sqrt {x - 2} 
\end{array}\)