Tìm x biết. a)x(x-3)+2x-6=0 b)9x^2-64=0

a)x(x-3)+2x-6=0

⇔$x^{}$ ($x - 3)^{}$ + $2(x - 3)^{}$= $0^{}$ 

⇔$(x - 3)(x + 2)^{}$= $0^{}$ 

⇔\(\left[ \begin{array}{1}x - 3=0\\x - 2=0\end{array} \right.\) 

⇔\(\left[ \begin{array}{l}x=3\\x=-2\end{array} \right.\) 

cho mình gửi câu a ạ

b)9x^2-64=0

⇔ (3x - 8)(3x + 8) = 0

⇔\(\left[ \begin{array}{l}3x- 8=0\\3x+8=0\end{array} \right.\) 

⇔\(\left[ \begin{array}{l}x=8/3\\x=-8/3\end{array} \right.\)

Cho mình gửi lại ạ