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Bạn tham khảo:

$a/$

$Na_2O+H_2O \to 2NaOH$

$n_{Na_2O}=0,25(mol)$

$n_{NaOH}=0,25.2=0,5(mol)$

$CM_{NaOH}=\frac{0,5}{0,5}=1M$

$b/$

$2NaOH+H_2SO_4 \to Na_2SO_4+H_2O$

$n_{H_2SO_4}=\frac{0,5}{2}=0,25(mol)$
$V_{ddH_2SO_4}=\frac{\frac{0,25.98.100}{20}}{1,14}=107,45(ml)$