sin (2x-pi/6)=0

$\begin{array}{l}
\sin \left( {2x - \dfrac{\pi }{6}} \right) = 0\\
 \Leftrightarrow 2x - \dfrac{\pi }{6} = k\pi \\
 \Leftrightarrow 2x = \dfrac{\pi }{6} + k\pi \\
 \Leftrightarrow x = \dfrac{\pi }{{12}} + \dfrac{{k\pi }}{2}\left( {k \in Z} \right)
\end{array}$