Điều chế C4H10 từ C2H4 :v

* Cách 1:

$C_2H_4+HCl\to CH_3-CH_2-Cl$

$2C_2H_5Cl+2Na\xrightarrow{{xt, t^o}} 2NaCl+ CH_3-CH_2-CH_2-CH_3$

* Cách 2: 

$C_2H_4+HBr\to CH_3-CH_2-Br$

$CH_3-CH_2Br+Mg\xrightarrow{{(CH_3)_2O}} C_2H_5MgBr$

$C_2H_5MgBr+CH_3CHO\to CH_3-CH_2-CH(CH_3)OMgBr$

$CH_3CH_2CH(CH_3)OMgBr+H_2O\to CH_3-CH_2-CH(OH)-CH_3+MgOHBr$

$CH_3-CH_2-CH(OH)-CH_3\xrightarrow{{H_2SO_4 đ, 170^oC}} H_2O+\left[ \begin{array}{l} CH_3-CH_2-CH=CH_2\\CH_3-CH=CH-CH_3\end{array} \right.$

$C_4H_8+H_2\xrightarrow{{Ni, t^o}} CH_3-CH_2-CH_2-CH_3$