2 cách nhá giúp mik vs nhanh nhé

@Bơ

Đáp án+Giải thích các bước giải:

`@`

`(2x-3)^2=25`
`(2x-3)^2=5^2`

\(\left[ \begin{array}{l}2x-3=5\\2x-3=-5\end{array} \right.\) 
\(\left[ \begin{array}{l}2x=5+3\\2x=-5+3\end{array} \right.\) 
\(\left[ \begin{array}{l}2x=8\\2x=-2\end{array} \right.\) 
\(\left[ \begin{array}{l}x=4\\x=-1\end{array} \right.\) 

Vậy \(\left[ \begin{array}{l}x=4\\x=-1\end{array} \right.\) 

`@`

`(2x-3)^2=25`

`<=>(2x+3)^2-25=0`

`<=>(2x+3)^2-(5)^2=0`

`<=>(2x-3-5)(2x-3+5)=0`

`<=>(2x-8)(2x+2)=0`

\(\left[ \begin{array}{l}2x-8=0\\2x+2=0\end{array} \right.\) 
\(\left[ \begin{array}{l}x=4\\x=-1\end{array} \right.\) 

Vậy \(\left[ \begin{array}{l}x=4\\x=-1\end{array} \right.\)