x.y = 5/6, y.z = 7/6, x.z = 5/7

$x.y=\dfrac{5}{6}⇔x=\dfrac{5}{6y}$

$y.z=\dfrac{7}{6}⇔z=\dfrac{7}{6y}$

$x.z=\dfrac{5}{7}$

$⇔\dfrac{5}{6y}.\dfrac{7}{6y}=\dfrac{5}{7}$

$⇔\dfrac{35}{36y^2}=\dfrac{5}{7}$

$⇔245=180y^2$

$⇔y^2=\dfrac{49}{36}$

$⇔y=±\dfrac{7}{6}$

Nếu $y=\dfrac{7}{6}⇒x=\dfrac{5}{6}:\dfrac{7}{6}=\dfrac{5}{7}$

$z=\dfrac{7}{6}:\dfrac{7}{6}=1$

$y=\dfrac{7}{6}⇒x=\dfrac{5}{6}:\dfrac{7}{6}=\dfrac{5}{7}$

$z=\dfrac{7}{6}:\dfrac{7}{6}=1$

Nếu$y=-\dfrac{7}{6}⇒x=\dfrac{5}{6}:(-\dfrac{7}{6})=-\dfrac{5}{7}$

$z=\dfrac{7}{6}:(-\dfrac{7}{6})=-1$