Giải pt : `x^2+|x|-6=0`

x2+|x|−6=0

<=>\(\left[ \begin{array}{l}x^{2}+x -6 = 0....x\geq 0 \\x^{2}-x-6 =0....x <0 \end{array} \right.\)  

<=> \(\left[ \begin{array}{l}\left \{ {{x=-3} ....x \geq 0\atop {x=2}} \right.\\\left \{ {{x=-2} ...x < 0\atop {x=3}} \right.\end{array} \right.\) 

<=> \(\left[ \begin{array}{l}x=2\\x=-2\end{array} \right.\) 

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