C2H5OH--> CH3COOH--> CH3COONa--> CH3COOH--> CH3COOC2H5 Hoàn thành Chuỗi pứ

$ C_2H_5OH + O_2 \xrightarrow{\text{Men giấm}} CH_3COOH + H_2O $ 

$ CH_3COOH + Na \rightarrow CH_3COONa + \dfrac{1}{2}H_2 ↑ $ 

$ CH_3COONa + H_2O \rightarrow CH_3COOH + NaOH $ 

$ CH_3COOH + C_2H_5OH ⇄ CH_3COOC_2H_5 + H_2O $  

(Điều kiện : $H_2SO_4đ,t^o$)