Tìm m để phương trình 6x+2m=2mx+2 có nghiệm nguyên dương

\(6x+2m=2mx+2\\↔6x-2mx=2-2m\\↔2x(3-m)=2-2m\\↔2x=\dfrac{2-2m}{3-m}\\↔x=\dfrac{2(1-m)}{2(3-m)}\\↔x=\dfrac{1-m}{3-m}\\ Pt\,\, co\,\, nghiem\,\, nguyen\,\, duong\\→\dfrac{1-m}{3-m}>0\\↔\begin{cases}1-m>0\\3-m>0\end{cases}\quad or\quad \begin{cases}1-m<0\\3-m<0\end{cases}\\↔\begin{cases}m<1\\m<3\end{cases}\quad or\quad \begin{cases}m>1\\m>3\end{cases}\\↔m<1\quad or\quad m>3\\Vay\,\, m<1\quad or\quad m>3\)