Giup minh từ c 1 đến 10 với ạ Ctlhn ❤️❤️

`9)`

`1.`

`\lim_{x \to +\infty} (2x+1)/(x-1) = \lim_{x \to +\infty} (2 + 1/x)/(1 - 1/x) = 2`

`2.`

`\lim_{x \to -\infty} (x^2+1)/(1-3x-5x^2) = \lim_{x \to -\infty} (1 + 1/x^2)/(1/x^2 - 3/x - 5) = -1/5`

`3.`

`\lim_{x \to -\infty} 3x(2x^2-1)/((5x-1)(x^2+2x)) = \lim_{x \to -\infty} (6x^3-3x)/(5x^3+9x^2-2x) = 6/5`

`4.`

`\lim_{x \to \pm\infty} (3x^3-2x+2)/(-2x^3+2x^2-1) = 3/(-2) = -1,5`

`5.`

`\lim_{x \to \pm\infty} (3x^3-2x^2-1)/(4x^4+3x-2) = \lim_{x \to \pm\infty} (3/x - 2/x^2 - 1/x^4)/(4 + 3/x^3 - 2/x^4) = 0/4 = 0`

`6.`

`\lim_{x \to \pm\infty} (x^3-2x^2-2)/(3x^2-x-1) = \lim_{x \to \pm\infty} x(1 - 2/x - 2/x^3)/(3 - 1/x - 1/x^2) = \pm\infty`

`7.`

`\lim_{x \to \pm\infty} (x^4-3x^2+1)/(-x^3+2x-2) = \lim_{x \to \pm\infty} x(1 - 3/x^2 + 1/x^4)/(-1 + 2/x^2 - 2/x^3) = \pm\infty`

`8.`

`\lim_{x \to \pm\infty} ((x-1)^2(7x+2)^2)/(2x+1)^4 = \lim_{x \to \pm\infty} (x^2(1-1/x)^2 \cdot x^2(7+2/x)^2)/(x^4(2+1/x)^4) = 49/16`

`9.`

`\lim_{x \to \pm\infty} ((2x-3)^2(4x+7)^3)/((3x-4)^2(5x^2-1)) = \lim_{x \to \pm\infty} (4x^2 \cdot 64x^3)/(9x^2 \cdot 5x^2) = \lim_{x \to \pm\infty} 256x^5/(45x^4) = \pm\infty`

`10.`

`\lim_{x \to +\infty} (x^2+1)/(2x^2-x+1) = 1/2`