(x-2)(x^2-3x+5)=x^3-2x^2

    (x-2)(x²-3x+5)=x³-2x²

⇔(x-2)(x²-3x+5)-x³+2x²=0

⇔(x-2)(x²-3x+5)-x²(x-2)=0

⇔(x-2)(x²-3x+5-x²)=0

⇔(x-2)(-3x+5)=0

⇔\(\left[ \begin{array}{l}x=x-2\\x=-3x+5\end{array} \right.\) 

⇔\(\left[ \begin{array}{l}x=2\\x=5/3\end{array} \right.\) 

S=2;5/3