Tìm giới hạn 1. lim [{x^3+8} / {x^2+11x+18}] x-->-2 2. lim [{(x+3)^3 - 27} / {x}] x-->0

1.

$\lim\limits_{x\to -2}\dfrac{x^3+8}{x^2+11x+18}$

$=\lim\limits_{x\to -2}\dfrac{x^2-2x+4}{x+9}$

$=\dfrac{4+4+4}{-2+9}=\dfrac{12}{7}$

2.

$\lim\limits_{x\to 0}\dfrac{(x+3)^3-3^3}{x}$

$=\lim\limits_{x\to 0}\dfrac{(x+3-3)[(x+3)^2+3(x+3)+9] }{x}$

$=\lim\limits_{x\to 0}(x+3)^2+3(x+3)+9$

$=27$