Tìm giới hạn 1. lim [{x-2} / {căn(x^2+5) - 3}] x-->2+ 2. lim [{1 - căn(x-2)} / {x^2-9}] x-->3-

1.

$\lim\limits_{x\to 2^+}\dfrac{x-2}{\sqrt{x^2+5}-3}$

$=\lim\limits_{x\to 2^+}\dfrac{(x-2)(\sqrt{x^2+5}+3)}{x^2-4}$

$=\lim\limits_{x\to 2^+}\dfrac{\sqrt{x^2+5}+3 }{x+2}$

$=\dfrac{\sqrt{4+5}+3}{2+2}$

$=\dfrac{3}{2}$

2.

$\lim\limits_{x\to 3^-}\dfrac{1-\sqrt{x-2}}{x^2-9}$

$=\lim\limits_{x\to 3^-}\dfrac{1-x+2}{(x-3)(x+3)(1+\sqrt{x-2})}$

$=\lim\limits_{x\to 3^-}\dfrac{-1}{(x+3)(1+\sqrt{x-2})}$

$=\dfrac{-1}{12}$