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Đáp án:

11) \(\left[ \begin{array}{l}
x = \dfrac{{103}}{{20}}\\
x =  - \dfrac{{97}}{{20}}
\end{array} \right.\)

Giải thích các bước giải:

\(\begin{array}{l}
1)\dfrac{{11}}{{12}} - 3x =  - \dfrac{4}{3}\\
 \to 3x = \dfrac{{11}}{{12}} + \dfrac{4}{3}\\
 \to 3x = \dfrac{9}{4}\\
 \to x = \dfrac{3}{4}\\
2)\left| {\dfrac{2}{5}x - \dfrac{1}{3}} \right| = \dfrac{4}{5}\\
 \to \left[ \begin{array}{l}
\dfrac{2}{5}x - \dfrac{1}{3} = \dfrac{4}{5}\\
\dfrac{2}{5}x - \dfrac{1}{3} =  - \dfrac{4}{5}
\end{array} \right.\\
 \to \left[ \begin{array}{l}
x = \dfrac{{17}}{6}\\
x =  - \dfrac{7}{6}
\end{array} \right.\\
3)\left( {\dfrac{1}{4} - \dfrac{{3x}}{{10}}} \right).\dfrac{1}{3} = \dfrac{{65}}{{12}}\\
 \to \dfrac{1}{4} - \dfrac{{3x}}{{10}} = \dfrac{{65}}{4}\\
 \to \dfrac{{3x}}{{10}} =  - 16\\
 \to x =  - \dfrac{{160}}{3}\\
4) - 10 - 6\left( {\dfrac{5}{6}x + 2} \right) = 0\\
 \to \dfrac{5}{6}x + 2 =  - \dfrac{5}{3}\\
 \to x =  - \dfrac{{22}}{5}\\
5){\left( {x - 2} \right)^3} =  - \dfrac{8}{{27}}\\
 \to x - 2 =  - \dfrac{2}{3}\\
 \to x = \dfrac{4}{3}\\
6){\left( {x - 2} \right)^2} = \dfrac{4}{9}\\
 \to \left| {x - 2} \right| = \dfrac{2}{3}\\
 \to \left[ \begin{array}{l}
x - 2 = \dfrac{2}{3}\\
x - 2 =  - \dfrac{2}{3}
\end{array} \right. \to \left[ \begin{array}{l}
x = \dfrac{8}{3}\\
x = \dfrac{4}{3}
\end{array} \right.\\
7)\dfrac{4}{3}:\dfrac{4}{5} = \dfrac{2}{3}:\dfrac{x}{{10}}\\
 \to \dfrac{5}{3} = \dfrac{{20}}{{3x}}\\
 \to x = 4\\
8)\dfrac{{13}}{3}.\dfrac{4}{x} = 20\\
 \to x = \dfrac{{13}}{{15}}\\
9)3x - 3 = 2x + 4\\
 \to x = 7\\
10)x\left( {3x - 2} \right) = 0\\
 \to \left[ \begin{array}{l}
x = 0\\
x = \dfrac{2}{3}
\end{array} \right.\\
11)\left[ \begin{array}{l}
\left| {2x - \dfrac{3}{{10}}} \right| - 2 = 8\\
\left| {2x - \dfrac{3}{{10}}} \right| - 2 =  - 8\left( l \right)
\end{array} \right.\\
 \to \left| {2x - \dfrac{3}{{10}}} \right| = 10\\
 \to \left[ \begin{array}{l}
2x - \dfrac{3}{{10}} = 10\\
2x - \dfrac{3}{{10}} =  - 10
\end{array} \right.\\
 \to \left[ \begin{array}{l}
x = \dfrac{{103}}{{20}}\\
x =  - \dfrac{{97}}{{20}}
\end{array} \right.\\
12){3^x} - {3^3}{.3^x} =  - 324\\
 \to  - {26.3^x} =  - 324\\
 \to {3^x} = \dfrac{{162}}{{13}}
\end{array}\)

( câu 12 kiến thức bạn chưa học nên k tìm đc x nhé )