25.5^3/7^0.5^5 tim x x+1/3=3^5:3^3 |1/2x+3/4|-1/3=0

Đáp án+giải thích các bước giải:

a)

$x+\dfrac{1}{3}=3^5:3^3$

$x+\dfrac{1}{3}=3^{5-3}$

$x+\dfrac{1}{3}=3^2$

$x+\dfrac{1}{3}=9$

$x=9-\dfrac{1}{3}$

$x=\dfrac{27}{3}-\dfrac{1}{3}$

$x=\dfrac{26}{3}$

Vậy......

b) 

$|\dfrac{1}{2}x+\dfrac{3}{4}|-\dfrac{1}{3}=0$

$|\dfrac{1}{2}x+\dfrac{3}{4}|=\dfrac{1}{3}$

TH1:

$\dfrac{1}{2}x+\dfrac{3}{4}=\dfrac{1}{3}$

$\dfrac{1}{2}x=\dfrac{1}{3}-\dfrac{3}{4}$

$\dfrac{1}{2}x=\dfrac{-5}{12}$

$x=\dfrac{-5}{12}:\dfrac{1}{2}$

$x=\dfrac{-5}{6}$

TH2:

$\dfrac{1}{2}x+\dfrac{3}{4}=\dfrac{-1}{3}$

$\dfrac{1}{2}x=\dfrac{-1}{3}-\dfrac{3}{4}$

$\dfrac{1}{2}x=\dfrac{-13}{12}$

$x=\dfrac{-13}{12}:\dfrac{1}{2}$

$x=\dfrac{-13}{6}$

Vậy...