Tìm x biết : 2x(3x-5)=10-6x

C1: 2x(3x-5) = 10 - 6x

<=> $6x^{2}$ - 10x = 10 - 6x

<=> $6x^{2}$ - 4x - 10 = 0

<=> $6x^{2}$ + 6x - 10x - 10 = 0

<=> 6x(x-1) - 10(x-1) = 0

<=> (6x-10)(x-1) = 0

<=> 6x - 10 = 0

         x - 1 = 0

<=> x = $\frac{5}{3}$  

         x = 1