${e,x^2-16x=0}$ ${k,x^4-2x^3+10x^2-20x=0}$ ${g,(2x-3)^2=(x+5)^2}$ ${f,x^2(x-1)-4x^2+8x-4=0}$

Đáp án:

a)x^2-16x=0

⇔x(x-16)=0

⇔x=0;16

b)x^4-2x^3+10x^2-20x=0

⇔x(x^3-2x^2+10x-20)=0

⇔x[x^2(x-2)+10(x-2)]=0

⇔x(x^2+10)(x-2)=0

⇔x=0;2

c)(2x-3)^2=(x+5)^2

⇔(2x-3)^2-(x+5)^2=0

⇔(2x-3+x+5)(2x-3-x-5)=0

⇔(3x+2)(x-8)=0

⇔x=-2/3;8

d)x^2(x-1)-4x^2+8x-4=0

⇔x^2(x-1)-4(x^2-2x+1)=0

⇔x^2(x-1)-4(x-1)^2=0

⇔(x-1)(x^2-4x+4)=0

⇔(x-1)(x-2)^2=0

⇔x=1;2