(x-5)(2x-4)=0 ((x mũ 2 +54 ) -32)2=244

Đáp án:

 $(x-5)(2x-4)=0$

$⇔$\(\left[ \begin{array}{l}x-5=0\\2x-4=0\end{array} \right.\) 

$⇔$\(\left[ \begin{array}{l}x=5\\x=2\end{array} \right.\) 

Vậy $\text{x ∈ {5 ; 2}}$

$[(x^2+54) -32]2 =244$

$⇔(x^2+54) -32 = 244 : 2$

$⇔(x^2+54 ) - 32 = 122$

$⇔x^2+54 = 122 +32$

$⇔x^2+54 = 154$

$⇔x^2 =154 - 54$

$⇔x^2=100$

$⇔x = ± 10$

Vậy $x=±10$