tim x : 2x^2+x=0 giai ho mik nhe

$2x^2+x=0$

$⇔x(2x+1)=0$

$⇔\left[ \begin{array}{l}x=0\\2x+1=0\end{array} \right.⇔\left[ \begin{array}{l}x=0\\x=\frac{-1}{2}\end{array} \right.$

Vậy $x=0$ hoặc $x=\frac{-1}{2}$.