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nếu câu trả lời hữu ích nhé!
Em tham khảo nha:
\(\begin{array}{l}
1)\\
a)\\
HCl \to {H^ + } + C{l^ - }\\
{H_2}S{O_3} \leftrightarrows 2{H^ + } + S{O_3}^{2 - }\\
{H_3}P{O_4} \leftrightarrows 3{H^ + } + P{O_4}^{3 - }\\
HClO \leftrightarrows {H^ + } + Cl{O^ - }\\
{H_2}S{O_4} \to 2{H^ + } + S{O_4}^{2 - }\\
C{H_3}COOH \leftrightarrows C{H_3}CO{O^ - } + {H^ + }\\
b)\\
NaOH \to N{a^ + } + O{H^ - }\\
Ba{(OH)_2} \to B{a^{2 + }} + 2O{H^ - }\\
c)\\
Al{(OH)_3} \leftrightarrows A{l^{3 + }} + 3O{H^ - }\\
Al{(OH)_3} \leftrightarrows Al{O_2}^ - + {H^ + } + {H_2}O\\
Zn{(OH)_2} \leftrightarrows Z{n^{2 + }} + 2O{H^ - }\\
Zn{(OH)_2} \leftrightarrows Zn{O_2}^{2 - } + 2{H^ + }\\
d)\\
BaC{l_2} \to B{a^{2 + }} + 2C{l^ - }\\
NaHC{O_3} \to N{a^ + } + HC{O_3}^ - \\
{(N{H_4})_2}S{O_4} \to 2N{H_4}^ + + S{O_4}^{2 - }\\
Al{(N{O_3})_3} \to A{l^{3 + }} + 3N{O_3}^ - \\
KMn{O_4} \to {K^ + } + Mn{O_4}^ - \\
F{e_2}{(S{O_4})_3} \to 2F{e^{3 + }} + 3S{O_4}^{2 - }\\
{K_2}HP{O_4} \to 2{K^ + } + HP{O_4}^{2 - }\\
N{a_2}S{O_3} \to 2N{a^ + } + S{O_3}^{2 - }
\end{array}\)
Hãy giúp mọi người biết câu trả lời này thế nào?
`a)`
`HCl->H^{+}+Cl^-`
`H_2SO_3` $\rightleftharpoons$ `2H^{+}+SO_3^{2-}`
`H_3PO_4` $\rightleftharpoons$ `H^{+}+H_2PO_4^-`
`H_2PO_4^-` $\rightleftharpoons$ `H^{+}+HPO_4^{2-}`
`HPO_4^{2-}` $\rightleftharpoons$ `H^{+}+PO_4^{3-}`
`HClO` $\rightleftharpoons$ `H^{+}+ClO^-`
`H_2SO_4->2H^{+}+SO_4^{2-}`
`CH_3COOH` $\rightleftharpoons$ `H^{+}+CH_3COO^-`
`b)`
`NaOH->Na^{+}+OH^-`
`Ba(OH)_2->Ba^{2+}+2OH^-`
`c)`
`Al(OH)_3` $\rightleftharpoons$ `Al^{3+}+3OH^-`
`Zn(OH)_2` $\rightleftharpoons$ `Zn^{2+}+2OH^-`
`d)`
`BaCl_2->Ba^{2+}+2Cl^-`
`NaHCO_3->Na^{+}+HCO_3^-`
`(NH_4)_2SO_4->2NH_4^{+}+SO_4^{2-}`
`Al(NO_3)_3->Al^{3+}+3NO_3^-`
`KMnO_4->K^{+}+MnO_4^-`
`Fe_2(SO_4)_3->2Fe^{3+}+3SO_4^{2-}`
`K_2HPO_4->2K^{+}+HPO_4^{2-}`
`Na_2SO_3->2Na^{+}+SO_3^{2-}`
Hãy giúp mọi người biết câu trả lời này thế nào?
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