Cần giải câu 6,7 cảm ơn nhiều.

Câu 6:

Phenyl acrylat: $C{H_2} = CHCOO{C_6}{H_5}$ a mol

Benzyl axetat: $C{H_3}COOC{H_2}{C_6}{H_5}$ b mol

${n_{KOH}} = \dfrac{{7,28}}{{56}} = 0,13\,\,mol$

$\left\{ \begin{gathered} 148a + 150b = 14,94 \hfill \\ 2a + b = 0,13 \hfill \\ \end{gathered} \right. \to \left\{ \begin{gathered} a = 0,03 \hfill \\ b = 0,07 \hfill \\ \end{gathered} \right.$

Muối:

$\begin{gathered} C{H_2} = CHCOOK:0,03\,\,mol\, \hfill \\ {C_6}{H_5}OK:0,03\,\,mol\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \hfill \\ C{H_3}COOK:0,07\,\,mol\,\,\,\,\,\,\,\,\,\,\,\,\,\, \hfill \\ \to m = 14,12\,\,gam\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \hfill \\ \end{gathered} $

Chọn C

Câu 7:

Metyl axetat: $C{H_3}COOC{H_3}$ x mol

Phenyl fomat: $HCOO{C_6}{H_5}$ y mol

${n_{NaOH}} = \dfrac{{9,2}}{{40}} = 0,23\,\,mol$

Ta có hệ phương trình:

$\left\{ \begin{gathered} 74x + 122y = 14,68 \hfill \\ x + 2y = 0,23 \hfill \\ \end{gathered} \right. \to \left\{ \begin{gathered} x = 0,05 \hfill \\ y = 0,09 \hfill \\ \end{gathered} \right.$

Muối: 

$\begin{gathered} C{H_3}COONa:0,05\,\,mol \hfill \\ HCOONa:0,09\,\,mol\,\,\,\,\, \hfill \\ {C_6}{H_5}ONa:0,09\,\,mol\,\,\,\,\, \hfill \\ \to m = 20,66\,\,gam\,\,\,\,\,\,\,\,\,\,\, \hfill \\ \end{gathered} $

Chọn A