(x-7)(2x-8)=0 bang bao nhieu

(x-7)(2x-8)=0

=> \(\left[ \begin{array}{l}x-7=0\\2x-8=0\end{array} \right.\) 

=> \(\left[ \begin{array}{l}x=7\\2x=8\end{array} \right.\) 

=> \(\left[ \begin{array}{l}x=7\\x=4\end{array} \right.\) 

Vậy x ∈ {7; 4}

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