Tìm x trong các tỉ lệ thức sau: a) 0,06 ; x = x : 24 b) 4 1/4 : 2 7/8 = x : 1,61

a) $0,06:x=x:24$

$⇒x^2=0,06.24=1,44$

\(⇒\left[ \begin{array}{l}x=\sqrt{1,44}=1,2\\x=-\sqrt{1,44}=-1,2\end{array} \right.\)

Vậy $x=(1,2,-1,2)$

b) $4\dfrac{1}{4}:2\dfrac{7}{8}=x:1,61$

$\dfrac{17}{4}:\dfrac{23}{8}=x:1,61$

$\dfrac{17}{4}.\dfrac{8}{23}=x:1,61$

$\dfrac{34}{23}=x:1,61$

$\dfrac{34}{23}.1,61=x$

$⇒\dfrac{119}{50}=x$