Tìm x (1/3x-8/13).(2,5+-7/5:x)=0

Đáp án:

\(x=\dfrac{24}{13}\ \text{hoặc x = $\dfrac{14}{25}$}\)

Giải thích các bước giải:

\(\bigg(\dfrac{1}{3}x-\dfrac{8}{13}\bigg).\bigg[2,5+\left (-\dfrac{7}{5}:x\right )\bigg]=0\\ \bigg(\dfrac{1}{3}x-\dfrac{8}{13}\bigg).\bigg[\dfrac{5}{2}+\left (-\dfrac{7}{5}:x\right )\bigg]=0\\ ⇔\left[ \begin{array}{l}\dfrac{1}{3}x-\dfrac{8}{13}=0\\\dfrac{5}{2}+\bigg(-\dfrac{7}{5}:x\bigg)=0\end{array} \right.\\ ⇔\left[ \begin{array}{l}\dfrac{1}{3}x=\dfrac{8}{13}\\-\dfrac{7}{5}:x=-\dfrac{5}{2}\end{array} \right.\\ ⇔\left[ \begin{array}{l}x=\dfrac{24}{13}\\x=\dfrac{14}{25}\end{array} \right.\\ \text{Vậy x = $\dfrac{24}{13}$ hoặc x = $\dfrac{14}{25}$}\)

chúc em học tốt!