Tính đạo hàm y =(x-2).căn x bình+1

\(y=(x-2).\sqrt{x^2+1}\\\Rightarrow y'=(x-2)'\sqrt{x^2+1}+(\sqrt{x^2+1})'(x-2)\\\quad\quad=\sqrt{x^2+1}+\dfrac{(x^2+1)'}{2\sqrt{x^2+1}}.(x-2)\\\quad\quad=\sqrt{x^2+1}+\dfrac{x(x-2)}{\sqrt{x^2+1}}\\\quad\quad=\dfrac{x^2+1+x^2-2x}{\sqrt{x^2+1}}\\\quad\quad=\dfrac{2x^2-2x+1}{\sqrt{x^2+1}}.\)