(1+2+3+....+100)(1 ² +2 ²+3 ² ...+10 ²)(65 ×111 - 13 ×15 ×37)

(1+2+3+...+100)($1^{2}$ +$2^{2}$ +$3^{2}$ +...+$10^{2}$ )(65.111-13.15.37)

=(1+2+3+...+100)($1^{2}$ +$2^{2}$ +$3^{2}$ +...+$10^{2}$ )(65.111-13.5.3.37)

=(1+2+3+...+100)($1^{2}$ +$2^{2}$ +$3^{2}$ +...+$10^{2}$ )(65.111-(13.5)(3.37))

=(1+2+3+...+100)($1^{2}$ +$2^{2}$ +$3^{2}$ +....+$10^{2}$ )(65.111-65.111)

=(1+2+3+...+100)($1^{2}$ +$2^{2}$ +$3^{2}$ +...+$10^{2}$ ).0

=0.